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Cisco CCNA Certification Exam Tutorial: Variance And Unequal Cost Load Balancing

To pass the CCNA exam, you’ve got to know how to work with and EIGRP -cost . You may not see much in production networks anymore, but you’ll see a lot of EIGRP, and part of fine-tuning your EIGRP network is making sure that all paths are in use while allowing for varying .

Using the command is the easy part – it’s getting the that’s the hard part with . With EIGRP, you just look in the and that’s it. With , you’ve got to run a debug to get the right .

The command is a when the value supplied with the command is multiplied by the lowest-cost , it must exceed the higher-cost in order for the higher-cost route to be added.

If that sounds complicated, it’s not. It’s one of those things that sounds difficult, but isn’t. Trust me!

In this example, R1 has two paths to 172.23.., but is currently using only one. By looking in the routing table, we’ve seen that the lowest-cost for network 172.23.. on R1 is 8576. This path goes through the 172.12.123. network. There is another valid path that uses the 172.12.13. network, but is not currently in use.

I 172.23../16 [100/8576] via 172.12.123.2, 00:00:53, Serial0

does not have a “show” command that displays all valid routes to a destination, as does EIGRP. The will show the current of the routes using the 512 route.

R1#debug

is on

19:17:51: : broadcasting request on Loopback0

19:17:51: : broadcasting request on Serial0

19:17:51: : broadcasting request on Serial1

19:17:51: : received update from 172.12.13.3 on Serial1

19:17:51: subnet 172.12.13., 23531 (neighbor 21531)

19:17:51: subnet 172.12.123., 23531 (neighbor 8476)

19:17:51: network 1..., 24031 (neighbor 8976)

19:17:51: network 2..., 22131 (neighbor 1600)

19:17:51: network 3..., 22031 (neighbor 501)

19:17:51: network 172.23.., 21631 (neighbor 1100)

R1(config)#router 1
R1(config-router)# 3
R1#show route 172.23..
Routing entry for 172.23../16
Known via “ 1″, distance 100, 8576
Redistributing via 1
Advertised by 1 (self originated)
Last update from 172.12.123.2 on Serial0, 00:00:01 ago
Routing Descriptor Blocks:
* 172.12.13.3, from 172.12.13.3, 00:00:20 ago, via Serial1
Route is 21631, traffic share count is 1
Total delay is 21000 microseconds, minimum bandwidth is 512 Kbit
Reliability 255/255, minimum MTU 1500 bytes
Loading 1/255, Hops
172.12.123.3, from 172.12.123.3, 00:00:20 ago, via Serial0
Route is 8576, traffic share count is 3
Total delay is 21000 microseconds, minimum bandwidth is 1544 Kbit
Reliability 255/255, minimum MTU 1500 bytes
Loading 1/255, Hops
172.12.123.2, from 172.12.123.2, 00:00:01 ago, via Serial0
Route is 8576, traffic share count is 3
Total delay is 21000 microseconds, minimum bandwidth is 1544 Kbit
Reliability 255/255, minimum MTU 1500 bytes
Loading 1/255, Hops

The for 172.23.. through the direct connection is 21631. A of 3 means that any route with a less than the best multiplied by the (in this case, 8576 x 3 = 25728) will be entered into the routing table. R1 now has three -cost paths to 172.23.. in its routing table, and will take place.

-cost takes some practice, but as you can see, once you get the it’s easy to work with. Just make sure you know how to get that !

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